Web1. Planet a3 P2 Mercury 0.059 0.058 Earth 1 1 Jupiter 140.6 141.1 Neptune 27162.3 27165.63 2. According to Kepler's 3rd … View the full answer Transcribed image text: Question 11 Calculate the cubes of the semi-major axes and the squares of the orbital periods of the planets listed in the table and enter them in the answer box. WebApr 13, 2024 · So far scientists have categorized exoplanets into the following types: Gas giant, Neptunian, super-Earth and terrestrial. The planets beyond our solar system are called “exoplanets,” and they come in …
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Web21 rows · Feb 11, 2024 · Orbital Period (days) 88.0: 224.7: 365.2: 27.3* 687.0: 4331: 10,747: 30,589: 59,800: 90,560: ... WebDec 16, 2024 · The formula for orbital eccentricity ( E ) is E=\frac {a-p} {a+p} E = a+pa−p With an eccentricity of 0.007, Venus' orbit is closest to being circular, while Mercury's, with an eccentricity of 0.21, is farthest. The eccentricity of Earth's orbit is 0.017. Did you find this page helpful? 👍 👎 Tips Find Your Next Great Science Fair Project! GO fit for 55 initiative
Educator Guide: Exploring Exoplanets with Kepler NASA/JPL Edu
WebFeb 13, 2024 · G – is the Gravitational constant, G = 6.67408 × 10⁻¹¹ m³ / (kg·s); and M – is the mass of the central star. If we substitute ω with 2 × π / T ( T - orbital period), and rearrange, we find that: R³ / T² = 4 × π²/ (G × M) = constant. … WebMay 28, 2024 · Notes: Distance is the semi-major axis in astronomical units (1 A.U. = 1.496× 10 8 km); rotation and revolution are the sidereal rotation period and sidereal orbital period, h = hours, d = Earth sidereal days; eccentricity is the orbital eccentricity = 1 – (perihelion/semi-major axis); and inclination is the tilt of the orbit with respect to the … WebThe square of the orbital period of any planet is proportional to the cube of the semimajor axis of the elliptical orbit. T 2 ∝ r 3 Given that for an object in a circular orbit, the … fit for 55 legislation implementation