WebLearning Objectives. 3.2.1 Write an expression for the derivative of a vector-valued function.; 3.2.2 Find the tangent vector at a point for a given position vector.; 3.2.3 Find the unit tangent vector at a point for a given position vector and explain its significance.; 3.2.4 Calculate the definite integral of a vector-valued function. Web01:34. Differentiate the function. f ( t) = 2 t 3 − 3 t 2 − 4 t. 00:50. Differentiate the function. f ( t) = 2 t 3 − 3 t 2 − 4 t. 00:48. Differentiate the function. g t) = ln 3 + t 2. 01:01. Find the derivative of the function. g ( t) = t 2 − 4 t 3.
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WebFind the Derivative - d/d@VAR g (t)= (4t)/ (t+1) g(t) = 4t t + 1 g ( t) = 4 t t + 1 Since 4 4 is constant with respect to t t, the derivative of 4t t+1 4 t t + 1 with respect to t t is 4 d dt[ t t+1] 4 d d t [ t t + 1]. 4 d dt [ t t+1] 4 d d t [ t t + 1] WebFind the Derivative - d/d@VAR G (t)= (1-2t)/ (3+t) G(t) = 1 − 2t 3 + t G ( t) = 1 - 2 t 3 + t crew rhymes
Differentiate a function with Step-by-Step Math Problem Solver
WebAug 8, 2016 · 1 Answer Eddie Aug 8, 2016 = − 6(t +3) (2t + 1)(3t − 1) Explanation: F (t) = ln[ (2t + 1)3 (3t − 1)4] break it up to make it easier.... = ln(2t + 1)3 − ln(3t −1)4 = 3ln(2t +1) − 4ln(3t − 1) d dt (3ln(2t +1) −4ln(3t − 1)) = 6 2t + 1 − 12 3t − 1 = 18t −6 − 24t −12 (2t + 1)(3t − 1) = −6t −18 (2t +1)(3t − 1) = − 6(t +3) (2t + 1)(3t − 1) Answer link WebThe objective of this paper is to study the existence of extremal solutions for nonlinear boundary value problems of fractional differential equations involving the ψ−Caputo derivative CDa+σ;ψϱ(t)=V(t,ϱ(t)) under integral boundary conditions ϱ(a)=λIν;ψϱ(η)+δ. Our main results are obtained by applying the monotone iterative technique combined with … WebSolution for Differentiate the function. g(t) = 2t-3/4 g'(t) = Q: Question 1 Apply the First Derivative Test to find the minimum value of f(x)=(2x^+2)/x² .Keep 4… A: The given problem is to find the minimum value of the given function using the first derivative… crew rhyming words